2x^2+5=3x^2-35

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Solution for 2x^2+5=3x^2-35 equation:


Simplifying
2x2 + 5 = 3x2 + -35

Reorder the terms:
5 + 2x2 = 3x2 + -35

Reorder the terms:
5 + 2x2 = -35 + 3x2

Solving
5 + 2x2 = -35 + 3x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x2' to each side of the equation.
5 + 2x2 + -3x2 = -35 + 3x2 + -3x2

Combine like terms: 2x2 + -3x2 = -1x2
5 + -1x2 = -35 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
5 + -1x2 = -35 + 0
5 + -1x2 = -35

Add '-5' to each side of the equation.
5 + -5 + -1x2 = -35 + -5

Combine like terms: 5 + -5 = 0
0 + -1x2 = -35 + -5
-1x2 = -35 + -5

Combine like terms: -35 + -5 = -40
-1x2 = -40

Divide each side by '-1'.
x2 = 40

Simplifying
x2 = 40

Take the square root of each side:
x = {-6.32455532, 6.32455532}

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